Eigtth circle theorem: 'Perpendicular bisects the chord'

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Perpendicular & chord


Perpendicular from the centre,A, cutting a chord of the circle.

CD is the chord, and AE is perpendicular to it.

Move C or D, and note the connection between lengths CE and DE.

If you want to alter the size of the circle, move A or B.

This is a Java Applet created using GeoGebra from www.geogebra.org - it looks like you don't have Java installed, please go to www.java.com

As CE is always the same as DE,you can see that 'the perpendicular from the centre to a chord bisects the chord'.



If you need them, the theorems are summarised here

Tim Devereux, Created with GeoGebra